15 points and brainliest for first answer

write the equation for a line that id perpendicular to the line 8x-4y=12 and passes through the origin

y = -(1/2)x

Step-by-step explanation:

given 8x-4y=12

arranging in slope-intercept form:

8x-4y=12

4y = 8x - 12 (divide both sides by 4)

y = 2x - 3

we can see that the slope of this line is the coefficient of x , which is 2.

The slope of a perpendicular line is the negative reciprocal of this number

m = -1/2

assembling the linear equation in point-slope form

y - y₁ = m (x - x₁)

given that the equation passes through the origin, then both x₁ and y₁=0

y - 0 = (-1/2) (x - 0)

y = (-1/2)x

y = -(1/2)x

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116