Asquare and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of the circle. what is the ratio of the area of the square to the area of the circle?

r=AB=AC=BC, AD=r/2, ED=DF=CD=squareroot(3.r)/2

The area of square is : (EF)^2=(squareroot(3.r))^2=3r^3

The area of circle is : (pi.r^2)

The ratio will be: 3/pi

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y