Me. will mark brainliest. a. s.a. p
a club volleyball league allows only the top 5% of athletes who try out to be part of the team. if the team tryout scorecard has a mean of 250 and a standard deviation of 15, which of the following can be used as a minimum qualifying score to join the volleyball league?

a. 13
b. 237
c. 251
d. 274

D. 274

Step-by-step explanation:

A normal distribution of the scores is assumed. In the figure attached, the standard normal distribution table is shown.

If only top 5% of athletes are part of the team, then we need to find the value of the table which has a probability of 95%, that value is between 1.64 and 1.65, so we interpolate it as 1.645. The table was made for a variable with mean = 0 and standard deviation (sd) equal to 1, therefore to refer the result to our variable we compute:

1.645 = (x - mean)/sd

x = 1.645*sd + mean

x = 1.645*15 + 250 ≈ 274

So, 95% of the scores are below 274, then 274 is the minimum qualifying score

add the table and i will answer correctly

step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right