What is the answer to this question someone pls: find three consecutive integers whose sum is -30

  -11, -10, -9

Step-by-step explanation:

The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.

I like to work "consecutive integer" problems using the average value of the integers involved. The average of two consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are three consecutive integers, so their average is the middle one.

If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...

  (x -1) +(x) + (x+1) = 3x = -30

  x = -30/3 = -10 . . . . . the same average we computed above.

  x -1 = -11 . . . . . the smaller of the other two integers

  x +1 = -9 . . . . . the larger of the other two integers

answer: idk

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it