The table and the graph below each show a different relationship between the same two variables, x and y: a table with two columns and 5 rows is shown. the column head for the left column is x, and the column head for the right column is y. the row entries in the table are 4,120 and 5,150 and 6,180 and 7,210. on the right of this table is a graph. the x-axis values are from 0 to 10 in increments of 2 for each grid line. the y-axis values on the graph are from 0 to 550 in increments of 110 for each grid line. a line passing through the ordered pairs 2, 110 and 4, 220 and 6, 330 and 8, 440 is drawn. how much more would the value of y be on the graph than its value in the table when x = 12?

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

29933333.33

step-by-step explanation:

dont't really have enough info here but its likely

sss for the three sides being congruent ( its stands for side side side)

or

sas   for side angle side.   so a side is congruent and and angle and a side