Let f(x) be a continuous and differentiable function on theinterval, 0< _ x< _ 1, and let g(x)=f(3x). the table below gives the values of f'(x), the derivatives of f(x). what is thevalue of g'(0.1)?
x 0.1 0.2 0.3 0.4 0.5 0.6
f'(x) 1.01 1.041 1.096 1.179 1.298 1.486

Step-by-step explanation:

We are given that f(x) be a continuous and differentiable function on interval [0,1]

We have to find the value of g'(0.1)

Differentiate w.r.t x

Substitute x=0.1

Substitute the value of f'(0.3) from given table

Hence, the value of g'(0.1)=3.288

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: