Speedy plumber charges $75 for a house call and 40 per hour for work done during the visit. drains-r-us charges $35 for a house call and $60 per hour for work done during the visit. how many hours of work result in the same total cost for a house call from either company and how much is the cost?

For 2 hours of work both the company's total charges would be same which is $155.

Step-by-step explanation:

Let the 'x' represents number of hours for work.

Also Let the 'y' represent the Total charge.

For Speedy Plumber Company:

Given:

Fixed charge = $75

Charge for each hour = $40

Amount of total charge is the sum of fixed charge and charge for each hour multiplied number of hours for work.

framing in equation form, we get;

For Drains-r-us Company:

Given:

Fixed charge = $35

Charge of labor for each hour = $60

Amount of total charge is the sum of fixed charge and charge for each hour multiplied number of hours of work.

framing in equation form, we get;

Now to find the hours of work result in the same total cost for a house call from either company, we will make both the equation equal we get;

Now we solve the equation,

Combining the like terms, we get;

Dividing both side by '20' using division property, we get;

Speedy Plumber Company charges after 2 hr =

Drains-r-us Company charges after 2 hr =

Hence For 2 hours of work both the company charges would be same which is $155.

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step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: