Achemistry teacher needs to mix a 20% salt solution with a 80% salt solution to make 15 qt of a 40% salt solution. how many quarts of each solution should the teacher mix to get the desired result?

10 quarts of 20 % salt solution mixed with 5 quarts of 80 % salt solution to make 15 quarts of 40 % salt solution

Solution:

The final mixture is 15 quarts

Let amount of 20% solution to be mixed, be x

Then, the amount of 80 % solution to be mixed is 15 - x

Thus, we can say,

"x" quarts of 20 % salt solution mixed with (15 - x) quarts of 80 % salt solution to make 15 quarts of 40 % salt solution

thus, we frame a equation as,

Thus 10 quarts of 20 % solution is mixed

Then, 15 - x = 15 - 10 = 5

5 quarts of 80 % salt solution is mixed

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet