An object moves at a constant rate along a circular path with radius 10 inches, and makes 3 revolutions in 2 seconds.
what is the linear velocity, in inches per second, of a point on the edge of the wheel?
15
2021
301
o 60

94.28 inches/second.

Step-by-step explanation:

The length of the circumference of the circular path with 10 inches radius is = inches.

Now, the point on the edge of the wheel moves by 3 revolutions in 2 seconds.

So, in 2 seconds the point moves a linear distance of (3 × 62.85) = 188.57 inches.

Therefore, the linear velocity of the point in inches per second is  inches per second.

(Answer)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15