If it took carlos 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 miles? (note: 1 mile = 5280 ft)
(1) the average speed at which carlos cycles from his house to the library yesterday was greater than 16 feet per second.
(2) the average speed at which carlos cycles from his house to the library yesterday was less than 18 feet per second.

Step-by-step explanation:

Given

time taken by Carlos to cycle is

For case (1)

Average speed

For

Distance traveled

Therefore Carlos might not be able to cover 6 miles with average speed of  16 ft/s

(2)

for 0.5 hr

distance traveled

Therefore Carlos might be able to cover more than 6 miles with

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14