Solve this application problem using a system of equations: the springfield movie theater sold adult tickets for $4.10 each and children's tickets for $2.70 each. last thursday, a total of $331.30 was collected from 89 movie watchers. how many of each type of ticket were sold on thursday?

65 adult tickets and 24 children tickets were sold

Solution:

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 4.10

Cost of 1 children ticket = $ 2.70

Last Thursday, a total of $331.30 was collected from 89 movie watchers

Number of movie watchers = 89

number of adult tickets sold + number of children tickets sold = 89

a + c = 89

c = 89 - a ----------- eqn 1

They collected a total of $ 331.30

Therefore, we frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = 331.30

4.1a + 2.7c = 331.3 ------ eqn 2

Substitute eqn 1 in eqn 2

4.1a + 2.7(89 - a) = 331.3

4.1a + 240.3 - 2.7a = 331.3

Combine the like terms

1.4a = 331.3 - 240.3

1.4a = 91

Substitute a = 65 in eqn 1

c = 89 - 65

Thus 65 adult tickets and 24 children tickets were sold

the correct answers i think are b. and d.

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step-by-step explanation: