Plsss answer, 35 pointss
write as a product of two polynomials.

1. x(y–5)–y(5–y)
2. (x–y)^2–a(y–x)
3. 2(3–b)+5(b–3)^2

1.

2.

3.

Step-by-step explanation:

1. The given polynomial is

We need to factor the second part to get:

We factor y-5 to obtain:

2. We have

We again factor -1 from the second part to get:

We now factor x-y to get:

3. We have

We factor negative 1 from the first part to get

We now factor b-3 to get:

We now simplify to get:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy