Find z z such that the proportion of observations that are less than z z in a standard normal distribution is 0.29 . 0.29. (enter your answer rounded to two decimal places.)z=

z = -0.55.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Find z z such that the proportion of observations that are less than z z in a standard normal distribution is 0.29 .

This is the value of Z that has a pvalue of 0.29.

So it is z = -0.55.

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point