Al, pablo, and marsha shared the driving on a 1,500-mile trip. which of the three drove the greatest distance on the trip? (1) al drove 1 hour longer than pablo but at an average rate of 5 miles per hour slower than pablo.(2) marsha drove 9 hours and averaged 50 miles per hour.

Pablo drove the greatest distance of 527 miles.

Missing Content:

Since information on Pablo is not given, it is impossible to solve this problem. Let us assume some scenario for Pablo. Say:

(3)Pablo averaged 52.7 miles per hour and drove for 10 hours.

Step-by-step explanation:

Using this information, we can find out the data on Al,

Al drove 1 hour longer than Pablo so,

Time Al drove= 10+1 =11 hours

Average rate of Al=Pablo's average rate-5= 52.7-5 = 47.7 miles per hour.

We know that,

Average Speed =

Distance =Average Speed x Time

Distance travelled by Al = 47.7 x 11 =524.7 miles

Distance Travelled by Marsha = 50 x 9=450 miles

Distance Travelled by Pablo= 52.7 x 10= 527 miles

As we can see that Pablo drove the greatest distance which is 527 miles.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

6 equilateral triangles