Adeadly virus runs through the beetles in big city. if there are 1280 beetles in the city and every week 20% of them die, how many beetles remain after 6 weeks?

336 beetles remain after 6 weeks.

Step-by-step explanation:

If there are 1280 beetles in the city and every week 20% of them die, then the rate is exponential. The formula for determining the number of beetles left in the city after t weeks would be

A = P(1 - r/n)^nt

Where

A represents the number of beetles left after t years.

P represents the initial number of beetles

r represents the death rate of the beetles.

n represents the periodic record of the death.

t represents the number of weeks.

From the information given,

P = 1280

r = 20/100 = 0.2

n = 1(recorded weekly)

t = 6 weeks

Therefore,

A = 1280(1 - 0.2/1)^1 × 6

A = 1280(0.8)^6

A = 336

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.