Point p(a, b) is in the first quadrant on the graph of the line x+y=4. a triangular region is shown on the diagram. what is the maximum area of the triangular region?

4

Step-by-step explanation:

Area of Triangular region (A) = a x b

b = 4 - a  (for point (a,b) and x + y = 4)

A = a x (4 - a) = - a² + 4a = -(a² - 4a + 4) + 4 = - (a - 2)² + 4

in the formula of parabola y = a(x - h)² + k, a= -1  the graph is pointed down where h=2 and k=4

The vertex is (2, 4)

The maximum area of triangular region is 4

answer: the answer is 127 degrees

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: