What is the slope of the line tangent to the curve y+2=x22−2siny at the point(2,0)

Step-by-step explanation:

hello :

y+2=x²−2siny

calculate y' :  y' = 2x -2y'cosy

when x= 2 and y=0   ( at the point(2,0) )   y' is the slope :

y' = 2(2)-2y'cos0   but cos0 =1

y' = 4 -2y'

3y' =4

so : y' = 4/3

the answer is d

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