Question
solve the problem by multiplying first.
a clothing store is having a sale on shirts and jeans. four shirts and two pairs of jeans cost $68. three
s 4s + 2) = 68
shirts and three pairs of jeans cost $81. the system of equations 3s + 3) = 81 models this
situation, where s is the cost of a shirt and is the cost of a pair of jeans. how much does one shirt an
one pair of jeans cost?
one shirt costs
and one pair of jeans cost $
.

A shirt cost $7 and a jean cost $20

From the question given, we have already been given the equations which are:

4s + 2j = 68 equation i

3s + 3j = 81 equation ii

Multiply equation i by 3

Multiply equation ii by 4

12s + 6j = 204 equation iii

12s + 12j = 324 equation iv

Subtract iii from iv

6j = 120

j = 120/6

j = 20

A jean cost $20

We can then calculate the value of the shirt and this will be:

4s + 2j = 68

4s + 2(20) = 68

4s + 40 = 68

4s = 68 - 40

4s = 28

s = 28/4

s = 7

A shirt cost $7

Therefore, a shirt cost $7 and a jean cost $20

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Step-by-step explanation:

4s + 2j = 682j = -4s + 68j = -2s + 34

3s + 3j = 81

3s + 3(-2s + 34) = 81

3s - 6s + 102 = 81

3s - 6s = 81 - 102

-3s = - 21

s = -21/-3

s = 7 < shirts cost 7 bucks

j = -2s + 34

j = -2(7) + 34

j = -14 + 34

j = 20 < jeans cost 20 bucks

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

pi x^2

step-by-step explanation:

pi times x squared