A) show that y superscript 6 baseline plus x minus 6 equals 0y6+x−6=0 is an implicit solution to startfraction dy over dx endfraction equals negative startfraction 1 over 6 y superscript 5 endfraction dy dx=− 1 6y5 on the interval (negative infinity comma 6 )(−[infinity],6). (b) show that xy superscript 9 baseline minus xy superscript 9 baseline cosine x equals 1xy9−xy9cosx=1 is an implicit solution to the differential equation startfraction dy over dx endfraction equals startfraction (negative x sine x plus cosine x minus 1 )y over 9 (x minus x cosine x )endfraction dy dx= (−xsinx+cosx−1)y 9(x−xcosx) on the interval (0 comma 2 pi )(0, 2π). (c) to verify the solution and the interval, convert y superscript 6 baseline plus x minus 6 equals 0y6+x−6=0 to explicit function(s).