In a survey, 20 people were asked how many magazines they had purchased during the previous year. the results are shown below. construct a histogram to represent the data. use 4 classes with a class width of 10, and begin with a lower class limit of -0.5. what is the approximate amount at the center? 6 15 3 36 25 18 12 18 5 30 24 7 0 22 33 24 19 4 12 9

See the explanation and figure attached.

Step-by-step explanation:

For this case the first step is order the data on increasing order and we got:

0,3,4,5,6,7,9,12,12,15,18,18,19,22,24,24,,25,30,33,36

For this case we assume that the lower class limit is -0.5 and each class present a width of 10 so we have this:

Interval          Frequency     Relative Frequency

[-0.5-9.5)             7                    7/20=0.35 (35%)

[9.5-19.5)             6                    6/20=0.30  (20%)

[19.5,29.5)           4                    4/20=0.2     (20%)

[29.5-39.5]          3                    3/20 =0.15   (15%)

Total                   20                              100%

The relative frequency is calculated as , where represent the frequency for the interval and n =20 the total of values given.

And then the histogram is on the figure attached.

As we can most of the values are on the left part so then we can conclude that the distribution on this case is skewed to the right. (Mode<Median<Mean)

idk wbu

step-by-step explanation: