Mathematics, 20.01.2020 21:31 creeper2737
Find the point of intersection of the given plane and the line that is perpendicular to the given plane and passes through (8, 4, 5). the xy-plane (x, y, z) = (1 (x, y, z) = ( + -/5 points find the point of intersection of the given plane and the line that is perpendicular to the given plane and passes through (2, 3, 7). the plane y = -12 (x, y, z) =( (x, y, z) = +-15 points find the equation of the sphere of radius 4 that lies above the xy-plane that just touches the xy-plane at the point (2, -7,0).
Answers: 2
Answer from: Quest
b
step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line
m = =
= - 3
with m = - 3 and (a, b) = (3, - 5), then
y - (- 5) = - 3(x - 3), that is
y + 5 = - 3(x - 3) → b
Answer from: Quest
is there supposed to be a diagram or a graph for this one? ?
step-by-step explanation:
Answer from: Quest
Ibelieve the answer would be b.
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