Graphing lines. plot the following lines:

a. y=3+2xy=3+2x
b. y=1+xy=1+x
c. y=−2+3xy=−2+3x
d. y=5xy=5x
e. y=4−2xy=4−2x

To graph a line of the form where is the slope and is the y-intercept.

A. To graph the line , we know that the slope is 2 and the y-intercept is (0, 3).

The fact that the slope of the line is 2 tells us that when x increases by 1 unit, y increases by 2 units. We know this because of the formula of the slope .

Therefore, another point with the y-intercept at the reference point is (0 + 1, 3 + 2) = (1, 5).

Connecting this points, we have the following graph.

B. To graph the line , we know that the slope is 1 and the y-intercept is (0, 1).

Another point with the y-intercept at the reference point is (0 + 1, 1 + 1) = (1, 2).

Connecting this points, we have the following graph.

C. To graph the line , we know that the slope is 3 and the y-intercept is (0, -2).

Another point with the y-intercept at the reference point is (0 + 1, -2 + 3) = (1, 1).

Connecting this points, we have the following graph.

D. To graph the line , we know that the slope is 5 and the y-intercept is (0, 0).

Another point with the y-intercept at the reference point is (0 + 1, 0 + 5) = (1, 5).

Connecting this points, we have the following graph.

E. To graph the line , we know that the slope is -2 and the y-intercept is (0, 4).

Another point with the y-intercept at the reference point is (0 + 1, 4 - 2) = (1, 2).

Connecting this points, we have the following graph.

good for u

step-by-step explanation:

i hope this is what you were looking for.

see attached graph