Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

So, total marbles in the bag = 6 + 4 = 10 marbles

Now,if E : Any given event, then

So, here

⇒ P(a Red ball)  = 3/5    ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag  = 10

So, here

⇒ P(a Blue marble)  = 2/5    ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble)  = 3/5 x 2/5  = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

step-by-step explanation: 2