If you toss four fair coins, in how many ways can you obtain at least one head? group of answer choicesa. 1/16b. 1/2c. 3/16d. 11/16e. 3/8

The correct answer is:

15/16

Step-by-step explanation:

In a toss of four fair coin, there are possibility of 16 occurrence because a coin have an head and a tail (2).

In 4 coins, we will have : 2⁴ = 16

Let S be the sample space, then:

S = { , HHHT, HHTT, HTTT, TTTH, TTHH, TTTH, , HTHT, THTH, HHTH, HTHH, TTHT,THHT, HTTH, THTT}

Let E₁ be the event that at least one head appears:

n(E₁) = 15

∴ Pr (E₁) = n(E₁)/ n(S)

             = 15/16

answer: i'm great at algebra

~coco

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x