After flying between two black holes, our engines have been a bit janky. the probability of one of any of our 8 power couplings failing is 10%: what’s the probability none fail? what’s the probability one fails? what’s the probability four fail? what’s the probability six fail? what’s the probability eight fail?

Step-by-step explanation:

We would apply the formula for binomial distribution. It is expressed as

P(x = r) = nCr × q^(n - r) × p^r

Where

p represents probability of success

q represents probability of failure.

n represents number of sample.

From the information given,

p = 10% = 10/100 = 0.1

q = 1 - q = 1 - 0.1 = 0.9

n = 8

1)The probability that none fails is

P(x = 0) = 8C0 × 0.9^(8 - 0) × 0.1^0

P(x = 0) = 0.43

2) The probability that one fails is

P(x = 1) = 8C1 × 0.9^(8 - 1) × 0.1^1

P(x = 1) = 0.38

3) The probability that four fails is

P(x = 4) = 8C4 × 0.9^(8 - 4) × 0.1^4

P(x = 4) = 0.0046

3) The probability that six fails is

P(x = 6) = 8C6 × 0.9^(8 - 6) × 0.1^6

P(x = 6) = 0.00002268

4) The probability that eight fails is

P(x = 8) = 8C8 × 0.1^(8 - 8) × 0.1^8

P(x = 8) = 0.00000001

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p