Aweather balloon is launched from the ground at a spot 250 yards from a 65 foot royal palm tree . what is the minimal angle of elevation at which the balloon must take off in order to avoid hitting the tree? assume that the balloon flies in a straight line and the angle of elevation stays constant.

Angle of elevation at which the balloon must take off in order to avoid hitting the tree is 5 degrees

Step-by-step explanation:

Given:

The height of the tree  = 65 foot

The distance between the tree and the spot from which the balloon is launched = 250 yards

To find:

The angle of elevation at which the balloon must take off in order to avoid hitting the tree = ?

Solution:

Converting the yards to feet

1 yards = 3 feet

250 yards = 3 x 250 = 750 yards

Refer the below figure, The angle x is the angle of elevation at which the the ball must be thrown so that it does not Hit the tree

Substituting the values

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars