Aset of final examinations grades in an introductory statistics course is normally distributed, with a mean of 75 and a standard deviation of 7. complete parts (a) through (d).

a.) what is the probability that a student scored below 87 on this exam?

b.) what is the probability that a student scored between 68 and 90?

c.) the probability is 25% that a student taking the test scores higher than what grade?

d.) if the professor grades on a curve (for example, the professor could give a

a)

And we can find this probability using the z table or excel and we got:

b)

And we can find this probability on this way:

And in order to find these probabilities we can use the table for the normal standard distribution, excel or a calculator.  

c)

So the value of height that separates the bottom 75% of data from the top 25% is 79.718.  

d) We can find the percentiles per each case for the original case using the z score first:

P(Z<0.857) =0.804[/tex]

That represent approximated the 80 percentile

And for the new case:

P(Z<2) =0.977[/tex]

That represent approximated the 97 percentile

So is better the second case since we are on a percentile higher respect the other people.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

Where and

We are interested on this probability

And the best way to solve this problem is using the normal standard distribution and the z score given by:

If we apply this formula to our probability we got this:

And we can find this probability using the z table or excel and we got:

Part b

And we can find this probability on this way:

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

Part c

For this part we want to find a value a, such that we satisfy this condition:

  (a)

  (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

But we know which value of z satisfy the previous equation so then we can do this:

And if we solve for a we got

So the value of height that separates the bottom 75% of data from the top 25% is 79.718.  

Part d: Assuming this question" If the professor grades on a curve (i.e. gives A's to the top 10% of the class, regardless of the test score), are you better off with a grade of 81 on this exam or a grade of 68 on a different exam, where the mean is 62 and the standard deviation is 3?"

We can find the percentiles per each case for the original case using the z score first:

P(Z<0.857) =0.804[/tex]

That represent approximated the 80 percentile

And for the new case:

That represent approximated the 97 percentile

So is better the second case since we are on a percentile higher respect the other people.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: