Aset of 10 cards consists of 5 red cards and 5 black cards. the cards are shuffled thoroughly and you turn cards over, one at a time, beginning with the top card. let x be the number of cards you turn over until you observe the first red card. the probability that x is greater than 2 is:

2/9

Step-by-step explanation:

given that a set of 10 cards consists of 5 red cards and 5 black cards. The cards are shuffled thoroughly and you turn cards over, one at a time, beginning with the top card.

Let X be the number of cards you turn over until you observe the first red card.

X can take values as 1,2,3,4,5 or 6.

No other possibility because at the worst 6th card has to be red

P(X>2) = 1-(P(X=1)+P(x=2))

P(X=1) = Prob for I card to be red =

P(x=2) Prob for I card black and second red =

i'm sure goog can you get that answer

no

step-by-step explanation: