Aj graphs the function latex: f\left(x\right)=-\left(x+2\right)^2 -1f ( x ) = − ( x + 2 ) 2 − 1 as shown below. on a coordinate plane, a parabola opens up. it goes through (negative 3, 0), has a vertex at (negative 2, negative 1), and goes through (negative 1, 0). a vertical dashed line at (negative 2, 0) is parallel to the y-axis. part 1: what mistake did aj make in the graph? part 2: evaluate any two x-values (between -5 and 5) into aj's function. show your work. how does your work prove that aj made a mistake in the graph?

Part 1 : The parabola opens down and it does not passes through the points (-3,0) and (-1,0) points.

Part 2 : (-3,-2) and (-1,-2) are the two values on the parabola.

Step-by-step explanation:

The general equation of a parabola with vertex at (α, β) and axis parallel to negative y-axis is given by

(x - α)² = - 4a(y - β) (1)

Part 1 : Now, the given parabola is f(x) = y = - (x + 2)² - 1

⇒ (x + 2)² = - (y + 1) (2)

Now, comparing equations (1) and (2), the vertex of the parabola is (-2,-1) and it opens down. and the axis of the parabola is the line x = - 2.

Now, it does not pass through the points (-3,0) and (-1,0) points.

Part 2 : Now, (-3,-2) and (-1,-2) are the two values on the parabola (2).

Because, it we put y = - 2, in equation (2) then we will get

(x + 2)² = - (- 2 + 1) = 1

⇒ x + 2 = ± 1

⇒ x = - 1 and - 3. (Answer)

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

36

step-by-step explanation: