Walleye is a common game fish. adult walleye have a length with a mean of 44 cm and a standard deviation of 4 cm, and the distribution of lengths is approximately normal. what fraction of fish are greater than 41 cm in length?
select one o a. -0.75 o b. 0.22 ? ? .077 o d. 0.75

b. 0.22

Step-by-step explanation:

Since the lengths of adult walleye fishes are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = lengths of walleye fishes.

µ = mean length

σ = standard deviation

From the information given,

µ = 44 cm

σ = 4 cm

We want to find the probability or fraction of fishes that are greater than 41 cm in length. It is expressed as

P(x > 41) = 1 - P(x ≤ 41)

For x = 41,

z = (41 - 44)/4 = - 0.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.22

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation: