For the total population of a large southern city, mean family income is $34,000, with a standard deviation (for the population) of $5,000. imagine that your are taking a subsample of 200 city residents. what is the probability that the sample mean exceeds $37,000?

Less than .0001

Step-by-step explanation:

The population and sample mean  family income are the same: $34,000.

The sample standard deviation is given by:

For any give income, X, the correspondent z-score of the distribution is given by:

For X = $37,000:

Traditional z-score tables present values up to 3.49 at the 99.98-th percentile. A z-score of 8.485, which is way above the upper represented limit, denotes an almost zero probability that the sample mean exceeds $37,000.

It is fair to say that the probability that the sample mean exceeds $37,000 is less than .0001

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

47 - 90 = 43

43 - 180 = x

x = 137