Each of the possible five outcomes of a random experiment is equally likely. the sample space is {a, b, c, d, e}. all outcomes are equally likely. let a denote the event {a, b}, and let b denote the event {c, d, e}. determine the following probabilities:
a) p(a)
b) p(b)
c) p(a')
d) p(a∪b)
e) p(a∩b)

a)

b)

c)

d) The probability for intersection on this case is 0 because the sets A and B not have any element in common, so then we have this

e) The intersection for this case is the empty set between the sets A and B so for this reason the probability is 0

P(A∩B)=0

Step-by-step explanation:

For this case we have the following sample space:

And we have defined the following events:

For this case we can find the probabilities for each event using the following definition of probability:

The total cases for this case are 5 , the possible cass for A are and for B are 3.

Usign this we have this:

Then we can find the following probabilites:

a) P(A)

b) P(B)

c) P(A')

Using the complement rule we have this:

d) P(A∪B)

For this case we can use the total probability rule and we got:

The probability for intersection on this case is 0 because the sets A and B not have any element in common, so then we have this

e) P(A∩B)

The intersection for this case is the empty set between the sets A and B so for this reason the probability is 0

P(A∩B)=0

answer: sensy

step-by-step explanation:

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without