What number completes the following equation
8×(40+7)=(8×+(8×7)

40

Step-by-step explanation:

8×(40+7)=(8×__)+(8×7)

several ways to do this, but the most simplistic (but probably not the quickest) way to do it is to simplify both sides of the equation and solve for the missing number,

lets substitute n for the missing number, hence equation becomes:

8×(40+7)=(8×n)+(8×7)   (by PEDMAS, evaluate terms inside parentheses first)

8 x (47) = (8n) + (56)

8 x 47 = 8n + 56 (next evaluate multiply)

376 = 8n + 56 (subtract 56 from both sides)

376 - 56 = 8n  (evaluate subtration and rearrange)

8n = 320  (divide both sides by 8)

n = 320 / 8

n = 40

step-by-step explanation:

sry but any answer choices

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116