The sum of two numbers is 52. one number is 3 times as large as the other number. which is the larger number

The two number are 39 and 13

Solution:

Let the two numbers be "a" and "b"

Let the larger number be "a" and the smaller number be "b"

Given that, sum of two numbers is 52

a + b = 52 eqn 1

One number is 3 times as large as the other number

Larger number = 3 times smaller number

a = 3b eqn 2

Let us solve eqn 1and eqn 2

Substitute eqn 2 in eqn 1

3b + b = 52

4b = 52

b = 13

Substitute b = 13 in eqn 2

a = 3(13)

a = 39

Thus the two number are 39 and 13

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

c and e

step-by-step explanation: c and e seem the most probable because a number less than 2 on a spinner with 4 equal sections would be 25% and e because all of the stacks contain 13 of that card.