The sum of the first and third of three consecutive integers is 136. find the three even integers

The three even integers are 66, 68 and 70

Solution:

Let the three consecutive even integers be x, x + 2, x + 4

Let the first integer be x

Let the second integer be x + 2

Let the third integer be x + 4

Given that, sum of the first and third of three consecutive integers is 136

Sum of first and third integer = 136

x + x + 4 = 136

2x + 4 = 136

2x = 136 - 4

2x = 132

x = 66

Thus the consecutive integers are:

first even integer = x = 66

second even integer = x + 2 = 66 + 2 = 68

third even integer = x + 4 = 66 + 4 = 70

Thus the three even integers are 66, 68 and 70

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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