Apomegranate is thrown from ground level straight up into the air at time t=0 with velocity 32 feet per second. its height at time t seconds is f(t)=−16t2+32t. find the time tg it hits the ground and the time th it reaches its highest point. what is the maximum height h? enter the exact answers.

It hit the ground at t=2

It reaches its highest point at t=1

Its maximum height =16

Step-by-step explanation:

The graph of the function of the height will be a parapola opening downward where it's x intercepts = the time where the object hit the ground and its maximum point = the point with the maximum point

The x intercepts are 0 when the object was thrown and 2 when it landed

The x coordinate of the vertex is in the middle of the two x intercepts so it will be 1

Substituting the x coordinate of the vertex gives us the y coordinate of the vertex which is the maximum hight 16

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right