a can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. one of the company's
clients needs a cylindrical can that has the same volume but is 15 cm tall. what must the new radius be to meet the
client's need? round to the nearest tenth of a centimeter.
2.7 cm
4.9 cm
o 7.3 cm
24.0 cm

Step-by-step explanation:

V=πr²h

=3.14*6*6*10

=1130.4 cm³

New cylinder:

h = 15cm

V= 1130.4  cm³

πr²h = 1130.4

3.14*r²*15=1130.4

r²=1130.4/15*3.14

r²=24

r=√24

r=4.898 = 4.9 cm

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°