Subtract – 7x – 9 from - 4x2 + 3x – 5.

-4x² + 10x + 4

Step-by-step explanation:

(-4x² + 3x - 5) - (-7x - 9)

-4x² + (3x - -7x) + (-5 - -9)

-4x² + (3x + 7x) + (-5 + 9)

-4x² + 10x + 4

10 * 563.67 = 5636.7

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.