Mathematics, 24.01.2020 03:31 xinkyx616

Using diaries for many weeks, a study on the lifestyles of visually impaired students was conducted. the students kept track of many lifestyle variables including how many hours of sleep obtained on a typical day. researchers found that visually impaired students averaged 8.65 hours of sleep, with a standard deviation of 1.93 hours. assume that the number of hours of sleep for these visually impaired students is normally distributed.
(a) what is the probability that a visually impaired student gets less than 6.2 hours of sleep?

(b) what is the probability that a visually impaired student gets between 6.8 and 10.93 hours of sleep?

(c) thirty percent of students get less than how many hours of sleep on a typical day?

hours

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Answer from: 916837

a) 0.1020

b) 0.7125

c) 7.64 hours

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.65, \sigma = 1.93$

(a) What is the probability that a visually impaired student gets less than 6.2 hours of sleep?

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2 - 8.65}{1.93}$

Z = -1.27

Z = -1.27 has a pvalue of 0.1020.

So the answer for a is 0.1020.

(b) What is the probability that a visually impaired student gets between 6.8 and 10.93 hours of sleep?

This is the pvalue of Z when X = 10.93 subtracted by the pvalue of Z when X = 6.8. So

X = 10.93

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10.93 - 8.65}{1.93}$

Z = 1.18

Z = 1.18 has a pvalue of 0.8810.

X = 6.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.8 - 8.65}{1.93}$

Z = -0.96

Z = -0.96 has a pvalue of 0.1685.

So the answer for b) is 0.8810 - 0.1685 = 0.7125.

This is the value of X in the 30th percentile, that is, the value of X when Z has a pvalue of 0.30. So it is X when Z = -0.525, since this happens between Z = -0.53 and Z = -0.52.

$Z = \frac{X - \mu}{\sigma}$

$-0.525 = \frac{X - 8.65}{1.93}$

X - 8.65 = -0.525*1.93

X = 7.64

The answer for c is 7.64 hours.

Answer from: Quest

the answer to this question is yes

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

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