What is the length of a rectangle when the length of the rectangle is 2(x+1) meters and the perimeter is 60 meters

Step-by-step explanation:

Given,

The length of a rectangle(l) = 2(x + 1) meters and  

The perimeter of a rectangle = 60 meters

To find, the width of a rectangle(b) = ?

We know that,

The perimeter of a rectangle = 2(l + b)

⇒  2(2(x + 1) + b) = 60

⇒  2(x + 1) + b =

⇒ b = 30 - 2(x + 1)

⇒ b = 30 - 2x - 2

⇒ b = 28 - 2x

⇒ b = 2(14 - x)

∴ The width of a rectangle(b) = 2(14 - x)

Hence, the width of a rectangle(b) = 2(14 - x)

50.6

step-by-step explanation:

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90