Line ab passes through point c(5,0) and is perpendicular to the line with the equation 3x-5y+17=0. determine the equation, in general form, for the line ab

The equation of line AB in general form is 5x + 3y - 25 = 0

Solution:

Given that we have to find the equation of line AB

The equation of line in slope intercept form is given as:

y = mx + c ------ eqn 1

Where, "m" is the slope of line and "c" is the y intercept

Given equation of line is:

3x - 5y + 17 = 0

Rearrange into slope intercept form

5y = 3x + 17

On comparing the above equation with eqn 1,

We know that,

Product of slope of line and slope of line perpendicular to given line is equal to -1

Now find the equation of line AB with slope and passes through point C(5,0)

Let us write the equation in general form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Thus equation of line AB in general form is 5x + 3y - 25 = 0

the answer is: -22 also a

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