The area of a playground is 234 yd2. the width of the playground is 5 yards longer than its length. find the length and width of the playground. (1 point)

Let x be the length of the playground. With this representation, the width may be expressed as x + 5. The area of a rectangular figure is the product of its length and width. 
 
                                              A = L x W
 
                                     A = (x)(x+5) = 234 yd²

Solving for the value of x in the equation gives an answer of x = 13 and x = -18. The second value of x is not applicable to the problem since a negative number cannot be a value for length. Below is the calculation of the dimensions.

                                     Length = x = 13 yards 
                                   Width = x + 5 = 18 yards

Thus, the length and width of the playground are 13 and 18 yards, respectively.