Dis the midpoint of ef.
ed = 4x + 6
df = 7x -9
find ef.

The line segment EF=11x-3

Step-by-step explanation:

Given that D is the midpoint of EF , ED=4x+6  and DF=7x-9

To find the EF :

Let EF is a line segment  and D its midpoint(given)

EF=ED+DF

=(4x+6)+(7x-9)

=4x+6+7x-9 ( adding the like terms )

=11x-3

Therefore EF=11x-3

Therefore the line segment EF=11x-3

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)