You bought your car for $12500 and it is depreciating at 13% per year. how long until it is only worth half of what you paid for it? what is your answer to the nearest year?

5 years

Step-by-step explanation:

We are given;

We are required to determine the time taken for the value of the car to depreciate to half the original value.

Therefore;

$6,250 = $12,500(1 - r/100)^n

0.5 = (1 - 13/100)^n

0.5 = 0.87^n

Introducing log on both sides;

log 0.5 = n log 0.87

Therefore;

n = log 0.5 ÷ log 0.87

  = 4.977

  = 5 years

Therefore, it takes 5 years for the value of the car to depreciate to half the initial value.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

pi x^2

step-by-step explanation:

pi times x squared