Find an equation for the plane tangent to the surface given by z = x 2 + y 4 + e xy at the point (1, 0, 2).

Step-by-step explanation:

Let

                               .

The partial derivatives of this function are

The tangent plane equation through a point is given by                    

In this case, we have

The values of the partial derivatives in this point are

So, the equation is

Therefore, the equation for the plane tangent to the surface at the point is given by

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it