Solve the system of linear equations. (enter your answers as a comma-separated list. if there is no solution, enter no solution. if the system has an infinite number of solutions, express x1, x2, and x3 in terms of the parameter t.)
2x1 + x2 − 2x3 = 4
4x1 + 2x3 = 10
−4x1 + 5x2 − 17x3 = −15

x1 = - 2.5

x2 = 29

x3 = 10

Step-by-step explanation:

2x1 + x2 − 2x3 = 4 - - - - - - - - - - 1

4x1 + 2x3 = 10 - - - - - - - - - - - - - 2

−4x1 + 5x2 − 17x3 = −15 - - - - - - - 3

Adding equation 2 to equation 3, it becomes

5x2 - 15x3 = - 5 - - - - - - - - - - -;-4

Multiplying equation 1 by 4 and equation 3 by 2, it becomes

8x1 + 4x2 − 8x3 = 16

8x1 + 10x2 − 34x3 = −30

Subtracting

- 6x2 + 26x3 = 46- - - - - - - - - - - - 5

Multiplying equation 4 by 6 and equation 5 by 5, it becomes

30x2 - 90x3 = - 30

- 30x2 + 130x3 = 230

Adding, it becomes

20x3 = 200

x3 = 200/20 = 10

Substituting x3 = 10 into equation 4, it becomes

5x2 - 15 × 10 = - 5

5x2 - 150 = - 5

5x2 = - 5 + 150 = 145

x2 = 145/5 = 29

Substituting x3 = 10 into equation 2, it becomes

4x1 + 2 × 10 = 10

4x1 = 10 - 20 = - 10

x1 = - 10/4 = - 2.5

step-by-step explanation:

this woman was an important writer and propagandist during the american revolution. she was a member of the committee of correspondence (in fact the committee was formed in her home) and was an advisor to many of the revolutionary leaders, including george washington and john adams. who was this revolutionary woman?

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day