Atotal of $500 was invested, part of it at 7 percent interest and the remainder at 8 percent .if the total yearly interest from both investments amounted to $38 ,how much was invested at 8 percent rate?

Step-by-step explanation:

Given that

Total  investment = $ 500

Let $x be invested at 7% and (500-x ) was invested at 8%

∴ The total interest after 1 year =$

According to problem,

= 38

⇔7x +4000 - 8x = 38×100

⇔ -x = 3800 - 4000

⇔x = $ 200

Therefore $(500-200)= $300 was invested at 8% rate

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.