a local train leaves the station in springfield traveling toward new york city at a constant rate of 55 mph. an express train headed for new york city on the same route leaves the station 1 hour later. the rate of the express train is 65 mph. which expression represents how long the local train had been traveling when the express train caught up with it?

The expression is 10t = 65

Step-by-step explanation:

At the point where the local train and the express train meet, both trains would have travelled an equal distance.

A local train leaves the station in Springfield traveling toward New York City at a constant rate of 55 mph.

Let t represent the time it spent in travelling a given distance.

Distance = speed × time

Therefore,

Distance travelled by the local train is 55 × t = 55t

The express train headed for New York City on the same route leaves the station 1 hour later. The rate of the express train is 65 mph. It means that total time spent travelling the same distance as the local train is t - 1

Therefore, distance travelled is

65(t - 1)

Since the distance travelled is the same, therefore,

55t = 65t - 65

65t - 55t = 65

10t = 65

t+1

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its a trick question

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