Ahemispherical tank is filled with water and has a diameter of 6 feet. if water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

The total weight of the water in a full tank, to the nearest pound is 3527 pounds per cubic foot

Step-by-step explanation:

Given:

Diameter  of the hemispherical tank = 6 feet

Weight of water per cubic foot =  62. 4 pounds

To Find:

The total weight of the water in a full tank, to the nearest pound?

Solution:

We know that the volume of a sphere is:

where  

r = is the radius

In the question we are given with diameter,

So

radius =

Radius = 3

We need the volume of the hemisphere

So the volume of the hemisphere will be half of the volume of teh sphere

Thus the volume of the hemisphere is

Now substituting the values

V=  56.52 cubic foot

Now, the total weight of water of:

W =  56.52 x 62.4

W= 3526.848 pounds per cubic foot

To the nearest pounds

W= 3527 pounds per cubic foot

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068