Between 1911 in 1990, the top of the leaning bell tower of pisa, italy moved toward the south at an average rate of 1.2 mm/y. the tower is 55m tall. in radians per second, what is the average regular speed of the towers top about its base?

Angular speed of the towers top about its base is rad per sec.

Step-by-step explanation:

Linear velocity of leaning bell tower 'v' = 1.2 mm per year

v =

v = 3.8 × meter per second

Height of the tower = 55 meter

From the formula of angular velocity,

v = rω

ω =

ω =

ω = rad per second.

Therefore, top of the tower is moving with an angular speed of rad per second.

this is a very good question

step-by-step explanation:

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